x^2+27x-19x-513=0

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Solution for x^2+27x-19x-513=0 equation:



x^2+27x-19x-513=0
We add all the numbers together, and all the variables
x^2+8x-513=0
a = 1; b = 8; c = -513;
Δ = b2-4ac
Δ = 82-4·1·(-513)
Δ = 2116
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2116}=46$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-46}{2*1}=\frac{-54}{2} =-27 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+46}{2*1}=\frac{38}{2} =19 $

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